How to Find the Size of an Array from a Pointer Pointing to the First Element of the Array
Introduction
When working with arrays in C or C++, it is important to know the size of the array. However, since arrays decay into pointers when passed to functions or stored in pointers, it can be challenging to find the size of an array when you only have a pointer pointing to the first element of the array. In this article, we will explore different approaches to solve this problem and find the size of an array from a pointer.
Method 1: Using the sizeof Operator
The simplest and most straightforward way to find the size of an array from a pointer is to use the sizeof
operator. In C and C++, the sizeof
operator can be used to determine the size of any data type, including arrays. By using the sizeof
operator with the array, we can get the total size of the array in bytes:
int main()
{
int days[] = {1, 2, 3, 4, 5};
int *ptr = days;
size_t size = sizeof(days) / sizeof(days[0]);
printf("Size of the array: %lu\n", size);
return 0;
}
In this code snippet, we first declare an array called "days" and initialize it with five elements. We then declare a pointer "ptr" and assign it the address of the first element of the array. To find the size of the array, we divide the total size of the array (found using sizeof
) by the size of each element of the array (found using sizeof
) and store the result in the variable "size". Finally, we print the size of the array using the printf
function.
Output:
Size of the array: 5
Method 2: Using Pointer Arithmetic
Another approach to find the size of an array from a pointer is to use pointer arithmetic. In C and C++, pointers can be used to traverse arrays, and we can use this property to find the size of an array. Here is an example:
int main()
{
int days[] = {1, 2, 3, 4, 5};
int *ptr = days;
int *endPtr = ptr;
while (*endPtr) {
endPtr++;
}
size_t size = endPtr - ptr;
printf("Size of the array: %lu\n", size);
return 0;
}
In this code snippet, we start with a pointer "ptr" pointing to the first element of the array. We then declare another pointer "endPtr" and initialize it with the same address as "ptr". We then iterate through the array by incrementing "endPtr" until we reach the end of the array (i.e., a null element). Finally, we find the size of the array by subtracting the addresses of "ptr" and "endPtr" and storing the result in the variable "size".
Output:
Size of the array: 5
Method 3: Combinations of Methods
In some cases, a combination of the above methods can be used to find the size of an array from a pointer. For example:
int main()
{
int days[] = {1, 2, 3, 4, 5};
int *ptr = days;
int *endPtr = ptr + sizeof(days) / sizeof(days[0]);
size_t size = endPtr - ptr;
printf("Size of the array: %lu\n", size);
return 0;
}
In this code snippet, we combine both the sizeof
and pointer arithmetic methods. We first calculate the address of the end of the array by adding the size of the array to the address of the first element of the array. We then find the size of the array by subtracting the addresses of "ptr" and "endPtr" and print the result.
Output:
Size of the array: 5
Conclusion
In conclusion, finding the size of an array from a pointer pointing to the first element of the array can be achieved using various methods. The most straightforward approach is to use the sizeof
operator and divide the total size of the array by the size of each element of the array. Alternatively, pointer arithmetic can be used to traverse the array and find the size by subtracting the addresses of the first and last elements. In some cases, a combination of both methods may be required. By understanding these techniques, you can accurately determine the size of an array even when you only have a pointer to the first element.